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`2:1``1:1``4:1``8:1`

Answer :

BSolution :

The rate of heat loss by a thin hollow sphere of thickness `Deltax`, mean radius r and made of density `rho` is given by <br> `mS=(dT)/(dt)=epsilonsigmaA(T^4-T_0^4)` <br> `(rho4pir^2Deltax)S(dT)/(dt)=-epsisigma4pir^2(T^4-T_0^4)` <br> `(dT)/(dt)=(epsisigma(T^4_T_0^4))/(SDeltax)` is independent of radius Hence the rate of cooling is same for both spheres.